log^8(3y-5)+10=12

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Solution for log^8(3y-5)+10=12 equation: 


Simplifying
log8(3y + -5) + 10 = 12

Reorder the terms:
g8lo(-5 + 3y) + 10 = 12
(-5 * g8lo + 3y * g8lo) + 10 = 12
(-5g8lo + 3g8loy) + 10 = 12

Reorder the terms:
10 + -5g8lo + 3g8loy = 12

Solving
10 + -5g8lo + 3g8loy = 12

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -5g8lo + -10 + 3g8loy = 12 + -10

Reorder the terms:
10 + -10 + -5g8lo + 3g8loy = 12 + -10

Combine like terms: 10 + -10 = 0
0 + -5g8lo + 3g8loy = 12 + -10
-5g8lo + 3g8loy = 12 + -10

Combine like terms: 12 + -10 = 2
-5g8lo + 3g8loy = 2

Reorder the terms:
-2 + -5g8lo + 3g8loy = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -5g8lo + 3g8loy = 0

The solution to this equation could not be determined.

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